Browser base game help

[zannza95]

<?php
include 'connect.php';

echo "text"
$piayerinfo = "select * from players where name = 'player1'";
$playerinfo2 = mysql_query($playerinfo) or die ("Could not select players");
$playerinfo3 = mysql_fetch_arrray($playerinfo2);
echo "Player1's email is". $playerinfo3['email'];
?>

heres my code
and im getting and error at ever line of $var and nothing is being put out to the screen, ive allrdy got the connect.php working.

[Epiales]

<?php
include 'connect.php';

echo "text"
$piayerinfo = "select * from players where name = 'player1'";
$playerinfo2 = mysql_query($playerinfo) or die ("Could not select players");
$playerinfo3 = mysql_fetch_arrray($playerinfo2);
echo "Player1's email is". $playerinfo3['email'];
?>

heres my code
and im getting and error at ever line of $var and nothing is being put out to the screen, ive allrdy got the connect.php working.

try echo "text";

Maybe?

[zannza95]

here is the http://www.christstruebride.com/worldof ... trance.php php file that is being used, i deleted it and still nothing is being posted, how would i use a die statement if there isn't finding a player1

[Epiales]

here is the http://www.christstruebride.com/worldof ... trance.php php file that is being used, i deleted it and still nothing is being posted, how would i use a die statement if there isn't finding a player1

I'm still new to much of this, but you can echo playerinfo:

Code: Select all

echo "playerinfo";

and see what that gives you.

Might be able to debug this way...

Code: Select all

$piayerinfo = "SELECT * FROM 'players'";
$result = mysql_query($playerinfo ) or trigger_error(mysql_error()." ".$piayerinfo );

I don't know a lot, but things that I"ve had to do before... Might help ya

[Epiales]

here is the http://www.christstruebride.com/worldof ... trance.php php file that is being used, i deleted it and still nothing is being posted, how would i use a die statement if there isn't finding a player1

Okay, change this:

$piayerinfo = "select * from players where name = 'player1'";

To this:

$playerinfo = "select * from players where name = 'player1'";

[zannza95]

Okay, change this:

$piayerinfo = "select * from players where name = 'player1'";

To this:

$playerinfo = "select * from players where name = 'player1'";
Epiales

Posts: 509
Joined: Wed Aug 14, 2013 8:38 pm


i dont see the diffrence?

[Epiales]

Okay, change this:

$piayerinfo = "select * from players where name = 'player1'";

To this:

$playerinfo = "select * from players where name = 'player1'";
Epiales

Posts: 509
Joined: Wed Aug 14, 2013 8:38 pm


i dont see the diffrence?

In your original query you have an " i " An eye.... Not an L

piayerinfo

I just changed it to an l for player

[zannza95]

it still does nothing i tried to echo out it ill try to query it on my connect server

[Epiales]

it still does nothing i tried to echo out it ill try to query it on my connect server

echo "Player1's email is". $playerinfo3['email'];


No quotation at the end? it's written wrong... Should be:

Code: Select all

echo "Player1's email is $playerinfo3[email]";

Try that?

[zannza95]

http://www.christstruebride.com/worldof ... onnect.php
this is what im getting when i simply call the $playerinfo = "Select * from players where name = 'player1'"
echo $playerinfo